Mixing Drinks

Question:

You have two drinks of the same size as on the left of the picture, A is red and B is blue. You take a spoonful from A and put it into B. After mixing well, you take an equal spoonful from B and put it into A.

Which cup has the more contaminated mixture? In other words, does A have more blue in the mix, or does B have more red in the mix?

Answer: (click to show)

They are equally contaminated!

The logical reasoning
A spoonful is taken from and given to each cup, so they are the same size at the end. Any red liquid taken from A must be in B, and so the same amount of blue liquid must have moved from B to A to make the amounts left equal.

The mathematical reasoning
say there is $$100$$ units in each of A and B to start, and a spoonful is $$10$$ units, these numbers are arbitrary. After the first swap, A has $$90$$ of red liquid, B has $$110$$ of liquid, of which $$\frac{1}{11}$$ is red.
After the second swap, A has $90+\frac{1}{11}\times 10 = 90 + \frac{10}{11}$ of red, so $100-\left(90 + \frac{10}{11}\right)=9+\frac{1}{11}$ of blue. B has $100-\frac{10}{11}\times 10 = 90 + \frac{10}{11}$ of blue and $9+\frac{1}{11}$ of red!